3310013013 has 4 divisors (see below), whose sum is σ = 4413350688. Its totient is φ = 2206675340.

The previous prime is 3310013011. The next prime is 3310013017. The reversal of 3310013013 is 3103100133.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3310013013 - 2¹ = 3310013011 is a prime.

It is a super-2 number, since 2×3310013013² = 21912372292458676338, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3310012983 and 3310013001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3310013011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 551668833 + ... + 551668838.

It is an arithmetic number, because the mean of its divisors is an integer number (1103337672).

Almost surely, 2^3310013013 is an apocalyptic number.

It is an amenable number.

3310013013 is a deficient number, since it is larger than the sum of its proper divisors (1103337675).

3310013013 is a wasteful number, since it uses less digits than its factorization.

3310013013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1103337674.

The product of its (nonzero) digits is 81, while the sum is 15.

The square root of 3310013013 is about 57532.7125468633. The cubic root of 3310013013 is about 1490.3098334707.

Adding to 3310013013 its reverse (3103100133), we get a palindrome (6413113146).

The spelling of 3310013013 in words is "three billion, three hundred ten million, thirteen thousand, thirteen".