331001310000041 has 8 divisors (see below), whose sum is σ = 331423038419904. Its totient is φ = 330579584480880.

The previous prime is 331001310000029. The next prime is 331001310000043. The reversal of 331001310000041 is 140000013100133.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 331001310000041 - 2⁴² = 326603263488937 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 331001309999974 and 331001310000019.

It is not an unprimeable number, because it can be changed into a prime (331001310000043) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 315198956 + ... + 316247346.

It is an arithmetic number, because the mean of its divisors is an integer number (41427879802488).

Almost surely, 2^{331001310000041} is an apocalyptic number.

It is an amenable number.

331001310000041 is a deficient number, since it is larger than the sum of its proper divisors (421728419863).

331001310000041 is a wasteful number, since it uses less digits than its factorization.

331001310000041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1450351.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 331001310000041 its reverse (140000013100133), we get a palindrome (471001323100174).

The spelling of 331001310000041 in words is "three hundred thirty-one trillion, one billion, three hundred ten million, forty-one", and thus it is an aban number.