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33102000131 = 231439217397
BaseRepresentation
bin11110110101000010…
…000111000000000011
310011102221020211120212
4132311002013000003
51020243103001011
623112402424335
72251204234004
oct366502070003
9104387224525
1033102000131
1113047241702
1264b99620ab
133176c40635
1418604031ab
15cdb11a08b
hex7b5087003

33102000131 has 4 divisors (see below), whose sum is σ = 34541217552. Its totient is φ = 31662782712.

The previous prime is 33102000097. The next prime is 33102000133. The reversal of 33102000131 is 13100020133.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13100020133 = 43304651631.

It is a cyclic number.

It is not a de Polignac number, because 33102000131 - 210 = 33101999107 is a prime.

It is a super-2 number, since 2×331020001312 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (33102000133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 719608676 + ... + 719608721.

It is an arithmetic number, because the mean of its divisors is an integer number (8635304388).

Almost surely, 233102000131 is an apocalyptic number.

33102000131 is a deficient number, since it is larger than the sum of its proper divisors (1439217421).

33102000131 is a wasteful number, since it uses less digits than its factorization.

33102000131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1439217420.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 33102000131 its reverse (13100020133), we get a palindrome (46202020264).

The spelling of 33102000131 in words is "thirty-three billion, one hundred two million, one hundred thirty-one", and thus it is an aban number.

Divisors: 1 23 1439217397 33102000131