Base | Representation |
---|---|
bin | 110000001010111000000… |
… | …000110100010101000001 |
3 | 102201110020100221200111222 |
4 | 300022320000310111001 |
5 | 413213303240240001 |
6 | 11012405044044425 |
7 | 461104066043006 |
oct | 60127000642501 |
9 | 12643210850458 |
10 | 3310212040001 |
11 | 1066942443859 |
12 | 45565b393715 |
13 | 1b01c825a519 |
14 | b63023d58ad |
15 | 5b18d6e761b |
hex | 302b8034541 |
3310212040001 has 2 divisors, whose sum is σ = 3310212040002. Its totient is φ = 3310212040000.
The previous prime is 3310212039931. The next prime is 3310212040021. The reversal of 3310212040001 is 1000402120133.
3310212040001 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2067096307600 + 1243115732401 = 1437740^2 + 1114951^2 .
It is a cyclic number.
It is not a de Polignac number, because 3310212040001 - 214 = 3310212023617 is a prime.
It is not a weakly prime, because it can be changed into another prime (3310212040021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1655106020000 + 1655106020001.
It is an arithmetic number, because the mean of its divisors is an integer number (1655106020001).
Almost surely, 23310212040001 is an apocalyptic number.
It is an amenable number.
3310212040001 is a deficient number, since it is larger than the sum of its proper divisors (1).
3310212040001 is an equidigital number, since it uses as much as digits as its factorization.
3310212040001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 3310212040001 its reverse (1000402120133), we get a palindrome (4310614160134).
The spelling of 3310212040001 in words is "three trillion, three hundred ten billion, two hundred twelve million, forty thousand, one".
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