Base | Representation |
---|---|
bin | 100101101000011111110111… |
… | …0111100001101101100001101 |
3 | 1121102001100011211110202221220 |
4 | 1023100333232330031230031 |
5 | 321341423343401412031 |
6 | 3132005051434313553 |
7 | 126503336462324511 |
oct | 11320775674155415 |
9 | 1542040154422856 |
10 | 331021433232141 |
11 | 96523446391a63 |
12 | 311622082888b9 |
13 | 11292258400182 |
14 | 5ba57469d4141 |
15 | 2840961876596 |
hex | 12d0feef0db0d |
331021433232141 has 8 divisors (see below), whose sum is σ = 444731085869664. Its totient is φ = 218996368041360.
The previous prime is 331021433231903. The next prime is 331021433232157. The reversal of 331021433232141 is 141232334120133.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 331021433232141 - 211 = 331021433230093 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (331021433230141) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 421146861226 + ... + 421146862011.
It is an arithmetic number, because the mean of its divisors is an integer number (55591385733708).
Almost surely, 2331021433232141 is an apocalyptic number.
It is an amenable number.
331021433232141 is a deficient number, since it is larger than the sum of its proper divisors (113709652637523).
331021433232141 is a wasteful number, since it uses less digits than its factorization.
331021433232141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 842293723371.
The product of its (nonzero) digits is 31104, while the sum is 33.
Adding to 331021433232141 its reverse (141232334120133), we get a palindrome (472253767352274).
The spelling of 331021433232141 in words is "three hundred thirty-one trillion, twenty-one billion, four hundred thirty-three million, two hundred thirty-two thousand, one hundred forty-one".
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