Base | Representation |
---|---|
bin | 100101101000100000001000… |
… | …1011001100001101000010110 |
3 | 1121102001101200010021202200111 |
4 | 1023101000101121201220112 |
5 | 321341431034400410314 |
6 | 3132005225045233234 |
7 | 126503360012221165 |
oct | 11321002131415026 |
9 | 1542041603252614 |
10 | 331022011341334 |
11 | 96523712748a55 |
12 | 31162349a0281a |
13 | 1129231b102b11 |
14 | 5ba579d6bd3dc |
15 | 28409974bcec4 |
hex | 12d1011661a16 |
331022011341334 has 4 divisors (see below), whose sum is σ = 496533017012004. Its totient is φ = 165511005670666.
The previous prime is 331022011341323. The next prime is 331022011341367. The reversal of 331022011341334 is 433143110220133.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 331022011341296 and 331022011341305.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82755502835332 + ... + 82755502835335.
It is an arithmetic number, because the mean of its divisors is an integer number (124133254253001).
Almost surely, 2331022011341334 is an apocalyptic number.
331022011341334 is a deficient number, since it is larger than the sum of its proper divisors (165511005670670).
331022011341334 is a wasteful number, since it uses less digits than its factorization.
331022011341334 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 165511005670669.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 331022011341334 its reverse (433143110220133), we get a palindrome (764165121561467).
The spelling of 331022011341334 in words is "three hundred thirty-one trillion, twenty-two billion, eleven million, three hundred forty-one thousand, three hundred thirty-four".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •