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33105041 is a prime number
BaseRepresentation
bin111111001001…
…0010010010001
32022021220120122
41332102102101
531433330131
63141320025
7551250104
oct176222221
968256518
1033105041
1117761342
12b106015
136b213a8
14457a73b
152d8dd7b
hex1f92491

33105041 has 2 divisors, whose sum is σ = 33105042. Its totient is φ = 33105040.

The previous prime is 33105031. The next prime is 33105109. The reversal of 33105041 is 14050133.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 31360000 + 1745041 = 5600^2 + 1321^2 .

It is a cyclic number.

It is not a de Polignac number, because 33105041 - 26 = 33104977 is a prime.

It is a super-2 number, since 2×331050412 = 2191887479223362, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (33105031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16552520 + 16552521.

It is an arithmetic number, because the mean of its divisors is an integer number (16552521).

Almost surely, 233105041 is an apocalyptic number.

It is an amenable number.

33105041 is a deficient number, since it is larger than the sum of its proper divisors (1).

33105041 is an equidigital number, since it uses as much as digits as its factorization.

33105041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 180, while the sum is 17.

The square root of 33105041 is about 5753.6980282250. The cubic root of 33105041 is about 321.0933984164.

Adding to 33105041 its reverse (14050133), we get a palindrome (47155174).

The spelling of 33105041 in words is "thirty-three million, one hundred five thousand, forty-one".