Base | Representation |
---|---|
bin | 110000001011101101000… |
… | …111111111011110101010 |
3 | 102201112112110122220001110 |
4 | 300023231013333132222 |
5 | 413222114344110010 |
6 | 11013033314531150 |
7 | 461135136041601 |
oct | 60135507773652 |
9 | 12645473586043 |
10 | 3311103113130 |
11 | 106725a42922a |
12 | 455869896ab6 |
13 | 1b030aa49927 |
14 | b63888aaa38 |
15 | 5b1e1a5e120 |
hex | 302ed1ff7aa |
3311103113130 has 16 divisors (see below), whose sum is σ = 7946647471584. Its totient is φ = 882960830160.
The previous prime is 3311103113027. The next prime is 3311103113161. The reversal of 3311103113130 is 313113011133.
It is a junction number, because it is equal to n+sod(n) for n = 3311103113097 and 3311103113106.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 55185051856 + ... + 55185051915.
It is an arithmetic number, because the mean of its divisors is an integer number (496665466974).
Almost surely, 23311103113130 is an apocalyptic number.
3311103113130 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
3311103113130 is an abundant number, since it is smaller than the sum of its proper divisors (4635544358454).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3311103113130 is a wasteful number, since it uses less digits than its factorization.
3311103113130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 110370103781.
The product of its (nonzero) digits is 243, while the sum is 21.
Adding to 3311103113130 its reverse (313113011133), we get a palindrome (3624216124263).
The spelling of 3311103113130 in words is "three trillion, three hundred eleven billion, one hundred three million, one hundred thirteen thousand, one hundred thirty".
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