Base | Representation |
---|---|
bin | 1001101000101111110… |
… | …00010001101001110011 |
3 | 1011122122211201210011101 |
4 | 10310113320101221303 |
5 | 20411104424011011 |
6 | 412040011025231 |
7 | 32631201666256 |
oct | 4642770215163 |
9 | 1148584653141 |
10 | 331113110131 |
11 | 11847379a461 |
12 | 5420913b217 |
13 | 252ba9b4a4b |
14 | 1205133d09d |
15 | 892ddad2c1 |
hex | 4d17e11a73 |
331113110131 has 2 divisors, whose sum is σ = 331113110132. Its totient is φ = 331113110130.
The previous prime is 331113110129. The next prime is 331113110161. The reversal of 331113110131 is 131011311133.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 331113110131 - 21 = 331113110129 is a prime.
It is a super-2 number, since 2×3311131101312 (a number of 24 digits) contains 22 as substring.
Together with 331113110129, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 331113110099 and 331113110108.
It is not a weakly prime, because it can be changed into another prime (331113110161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165556555065 + 165556555066.
It is an arithmetic number, because the mean of its divisors is an integer number (165556555066).
Almost surely, 2331113110131 is an apocalyptic number.
331113110131 is a deficient number, since it is larger than the sum of its proper divisors (1).
331113110131 is an equidigital number, since it uses as much as digits as its factorization.
331113110131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81, while the sum is 19.
Adding to 331113110131 its reverse (131011311133), we get a palindrome (462124421264).
The spelling of 331113110131 in words is "three hundred thirty-one billion, one hundred thirteen million, one hundred ten thousand, one hundred thirty-one".
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