Base | Representation |
---|---|
bin | 11110110101101000… |
… | …010010110110010011 |
3 | 10011110122002101201121 |
4 | 132311220102312103 |
5 | 1020303133311011 |
6 | 23113401143111 |
7 | 2251355304454 |
oct | 366550226623 |
9 | 104418071647 |
10 | 33112010131 |
11 | 13051959332 |
12 | 650118aa97 |
13 | 3179036905 |
14 | 186188b12b |
15 | cdbe45e71 |
hex | 7b5a12d93 |
33112010131 has 2 divisors, whose sum is σ = 33112010132. Its totient is φ = 33112010130.
The previous prime is 33112010059. The next prime is 33112010147. The reversal of 33112010131 is 13101021133.
It is an a-pointer prime, because the next prime (33112010147) can be obtained adding 33112010131 to its sum of digits (16).
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-33112010131 is a prime.
It is a super-2 number, since 2×331120101312 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (33112010161) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16556005065 + 16556005066.
It is an arithmetic number, because the mean of its divisors is an integer number (16556005066).
Almost surely, 233112010131 is an apocalyptic number.
33112010131 is a deficient number, since it is larger than the sum of its proper divisors (1).
33112010131 is an equidigital number, since it uses as much as digits as its factorization.
33112010131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 33112010131 its reverse (13101021133), we get a palindrome (46213031264).
The spelling of 33112010131 in words is "thirty-three billion, one hundred twelve million, ten thousand, one hundred thirty-one".
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