Base | Representation |
---|---|
bin | 100101101001001110110000… |
… | …0010111000001011101001011 |
3 | 1121102101222001220000110120102 |
4 | 1023102131200113001131023 |
5 | 321400101100301130011 |
6 | 3132123222504320015 |
7 | 126513532551502061 |
oct | 11322354027013513 |
9 | 1542358056013512 |
10 | 331122120333131 |
11 | 96562114657216 |
12 | 3117982817300b |
13 | 1129b8b3383a3a |
14 | 5baa578dd2031 |
15 | 28433a608673b |
hex | 12d27605c174b |
331122120333131 has 4 divisors (see below), whose sum is σ = 336550351814064. Its totient is φ = 325693888852200.
The previous prime is 331122120333047. The next prime is 331122120333143. The reversal of 331122120333131 is 131333021221133.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-331122120333131 is a prime.
It is a super-2 number, since 2×3311221203331312 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 331122120333094 and 331122120333103.
It is not an unprimeable number, because it can be changed into a prime (331122120303131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2714115740375 + ... + 2714115740496.
It is an arithmetic number, because the mean of its divisors is an integer number (84137587953516).
Almost surely, 2331122120333131 is an apocalyptic number.
331122120333131 is a deficient number, since it is larger than the sum of its proper divisors (5428231480933).
331122120333131 is an equidigital number, since it uses as much as digits as its factorization.
331122120333131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5428231480932.
The product of its (nonzero) digits is 5832, while the sum is 29.
Adding to 331122120333131 its reverse (131333021221133), we get a palindrome (462455141554264).
The spelling of 331122120333131 in words is "three hundred thirty-one trillion, one hundred twenty-two billion, one hundred twenty million, three hundred thirty-three thousand, one hundred thirty-one".
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