Base | Representation |
---|---|
bin | 110000001011110100110… |
… | …100011010110110100111 |
3 | 102201112212110120012002110 |
4 | 300023310310122312213 |
5 | 413222400420400403 |
6 | 11013054205412103 |
7 | 461141264210502 |
oct | 60136464326647 |
9 | 12645773505073 |
10 | 3311232200103 |
11 | 1067316287183 |
12 | 4558a4b6a033 |
13 | 1b032b705959 |
14 | b639bab0139 |
15 | 5b1ed05c103 |
hex | 302f4d1ada7 |
3311232200103 has 24 divisors (see below), whose sum is σ = 4462787103600. Its totient is φ = 2183819823360.
The previous prime is 3311232200077. The next prime is 3311232200137. The reversal of 3311232200103 is 3010022321133.
It is not a de Polignac number, because 3311232200103 - 214 = 3311232183719 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3311232200103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3311232204103) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 16789023 + ... + 16985103.
It is an arithmetic number, because the mean of its divisors is an integer number (185949462650).
Almost surely, 23311232200103 is an apocalyptic number.
3311232200103 is a deficient number, since it is larger than the sum of its proper divisors (1151554903497).
3311232200103 is a wasteful number, since it uses less digits than its factorization.
3311232200103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 196687 (or 196560 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 3311232200103 its reverse (3010022321133), we get a palindrome (6321254521236).
The spelling of 3311232200103 in words is "three trillion, three hundred eleven billion, two hundred thirty-two million, two hundred thousand, one hundred three".
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