Base | Representation |
---|---|
bin | 100101101001010011110111… |
… | …1100101001011010011101111 |
3 | 1121102110000102222212220020012 |
4 | 1023102213233211023103233 |
5 | 321400241103424314413 |
6 | 3132132241354043435 |
7 | 126514402142603246 |
oct | 11322475745132357 |
9 | 1542400388786205 |
10 | 331133113119983 |
11 | 96566845808729 |
12 | 3117b99571957b |
13 | 1129c945954145 |
14 | 5baacdcd4595d |
15 | 28437eb19d7a8 |
hex | 12d29ef94b4ef |
331133113119983 has 2 divisors, whose sum is σ = 331133113119984. Its totient is φ = 331133113119982.
The previous prime is 331133113119943. The next prime is 331133113120013. The reversal of 331133113119983 is 389911311331133.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 331133113119983 - 210 = 331133113118959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (331133113119943) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165566556559991 + 165566556559992.
It is an arithmetic number, because the mean of its divisors is an integer number (165566556559992).
Almost surely, 2331133113119983 is an apocalyptic number.
331133113119983 is a deficient number, since it is larger than the sum of its proper divisors (1).
331133113119983 is an equidigital number, since it uses as much as digits as its factorization.
331133113119983 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 472392, while the sum is 50.
The spelling of 331133113119983 in words is "three hundred thirty-one trillion, one hundred thirty-three billion, one hundred thirteen million, one hundred nineteen thousand, nine hundred eighty-three".
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