Base | Representation |
---|---|
bin | 11110110101101110… |
… | …111000001111000101 |
3 | 10011110202100002100121 |
4 | 132311232320033011 |
5 | 1020304104024013 |
6 | 23113502141541 |
7 | 2251406053522 |
oct | 366556701705 |
9 | 104422302317 |
10 | 33113736133 |
11 | 13052928085 |
12 | 65018818b1 |
13 | 31794bc40a |
14 | 1861bba149 |
15 | cdc18758d |
hex | 7b5bb83c5 |
33113736133 has 4 divisors (see below), whose sum is σ = 33118334188. Its totient is φ = 33109138080.
The previous prime is 33113736013. The next prime is 33113736137. The reversal of 33113736133 is 33163731133.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 28003344964 + 5110391169 = 167342^2 + 71487^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-33113736133 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (33113736137) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2288208 + ... + 2302633.
It is an arithmetic number, because the mean of its divisors is an integer number (8279583547).
Almost surely, 233113736133 is an apocalyptic number.
It is an amenable number.
33113736133 is a deficient number, since it is larger than the sum of its proper divisors (4598055).
33113736133 is an equidigital number, since it uses as much as digits as its factorization.
33113736133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4598054.
The product of its digits is 30618, while the sum is 34.
Subtracting 33113736133 from its reverse (33163731133), we obtain a triangular number (49995000 = T9999).
The spelling of 33113736133 in words is "thirty-three billion, one hundred thirteen million, seven hundred thirty-six thousand, one hundred thirty-three".
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