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33114100220431 is a prime number
BaseRepresentation
bin1111000011101111110100…
…01011100100001000001111
311100020200021120122210100021
413201313322023210020033
513320020134124023211
6154232224014243011
76655262162461216
oct741677213441017
9140220246583307
1033114100220431
11a60767a32316a
1238698991b6467
131562852a7a689
14826a33c2807d
153c6591585771
hex1e1dfa2e420f

33114100220431 has 2 divisors, whose sum is σ = 33114100220432. Its totient is φ = 33114100220430.

The previous prime is 33114100220417. The next prime is 33114100220473. The reversal of 33114100220431 is 13402200141133.

It is a weak prime.

It is an emirp because it is prime and its reverse (13402200141133) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 33114100220431 - 211 = 33114100218383 is a prime.

It is a super-2 number, since 2×331141002204312 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 33114100220396 and 33114100220405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (33114100220731) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16557050110215 + 16557050110216.

It is an arithmetic number, because the mean of its divisors is an integer number (16557050110216).

Almost surely, 233114100220431 is an apocalyptic number.

33114100220431 is a deficient number, since it is larger than the sum of its proper divisors (1).

33114100220431 is an equidigital number, since it uses as much as digits as its factorization.

33114100220431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 33114100220431 its reverse (13402200141133), we get a palindrome (46516300361564).

The spelling of 33114100220431 in words is "thirty-three trillion, one hundred fourteen billion, one hundred million, two hundred twenty thousand, four hundred thirty-one".