Base | Representation |
---|---|
bin | 1100010101100000… |
… | …0010101101100001 |
3 | 22112210000021012011 |
4 | 3011120002231201 |
5 | 23240210222423 |
6 | 1304331032521 |
7 | 145026361360 |
oct | 30530025541 |
9 | 8483007164 |
10 | 3311414113 |
11 | 144a230487 |
12 | 784b9b741 |
13 | 40a07a747 |
14 | 235b0b7d7 |
15 | 145aa9b0d |
hex | c5602b61 |
3311414113 has 4 divisors (see below), whose sum is σ = 3784473280. Its totient is φ = 2838354948.
The previous prime is 3311414111. The next prime is 3311414143. The reversal of 3311414113 is 3114141133.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 3311414113 - 21 = 3311414111 is a prime.
It is not an unprimeable number, because it can be changed into a prime (3311414111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 236529573 + ... + 236529586.
It is an arithmetic number, because the mean of its divisors is an integer number (946118320).
Almost surely, 23311414113 is an apocalyptic number.
It is an amenable number.
3311414113 is a deficient number, since it is larger than the sum of its proper divisors (473059167).
3311414113 is an equidigital number, since it uses as much as digits as its factorization.
3311414113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 473059166.
The product of its digits is 432, while the sum is 22.
The square root of 3311414113 is about 57544.8878094310. The cubic root of 3311414113 is about 1490.5200822469.
Adding to 3311414113 its reverse (3114141133), we get a palindrome (6425555246).
The spelling of 3311414113 in words is "three billion, three hundred eleven million, four hundred fourteen thousand, one hundred thirteen".
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