Base | Representation |
---|---|
bin | 100101101001011001000000… |
… | …0111010100000100101000111 |
3 | 1121102111001220120102200020021 |
4 | 1023102302000322200211013 |
5 | 321400431200140434142 |
6 | 3132141303551120011 |
7 | 126515242344134134 |
oct | 11322620072404507 |
9 | 1542431816380207 |
10 | 331144141343047 |
11 | 9657049497296a |
12 | 31181b52b13007 |
13 | 112a09b2680a16 |
14 | 5bab66788158b |
15 | 2843c44465267 |
hex | 12d2c80ea0947 |
331144141343047 has 2 divisors, whose sum is σ = 331144141343048. Its totient is φ = 331144141343046.
The previous prime is 331144141343021. The next prime is 331144141343069. The reversal of 331144141343047 is 740343141441133.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-331144141343047 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 331144141342994 and 331144141343012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (331144141341047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165572070671523 + 165572070671524.
It is an arithmetic number, because the mean of its divisors is an integer number (165572070671524).
Almost surely, 2331144141343047 is an apocalyptic number.
331144141343047 is a deficient number, since it is larger than the sum of its proper divisors (1).
331144141343047 is an equidigital number, since it uses as much as digits as its factorization.
331144141343047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 580608, while the sum is 43.
The spelling of 331144141343047 in words is "three hundred thirty-one trillion, one hundred forty-four billion, one hundred forty-one million, three hundred forty-three thousand, forty-seven".
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