Base | Representation |
---|---|
bin | 1111000011111011001011… |
… | …10000011000111000111011 |
3 | 11100021021000200110212011001 |
4 | 13201331211300120320323 |
5 | 13320120132200100011 |
6 | 154235113153545431 |
7 | 6655566300665233 |
oct | 741754560307073 |
9 | 140237020425131 |
10 | 33120200003131 |
11 | a60a21a50719a |
12 | 386aabbb75277 |
13 | 15632b5712057 |
14 | 827051daccc3 |
15 | 3c67ebd2d7c1 |
hex | 1e1f65c18e3b |
33120200003131 has 2 divisors, whose sum is σ = 33120200003132. Its totient is φ = 33120200003130.
The previous prime is 33120200003069. The next prime is 33120200003243. The reversal of 33120200003131 is 13130000202133.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-33120200003131 is a prime.
It is a super-2 number, since 2×331202000031312 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 33120200003099 and 33120200003108.
It is not a weakly prime, because it can be changed into another prime (33120200000131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16560100001565 + 16560100001566.
It is an arithmetic number, because the mean of its divisors is an integer number (16560100001566).
Almost surely, 233120200003131 is an apocalyptic number.
33120200003131 is a deficient number, since it is larger than the sum of its proper divisors (1).
33120200003131 is an equidigital number, since it uses as much as digits as its factorization.
33120200003131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 33120200003131 its reverse (13130000202133), we get a palindrome (46250200205264).
The spelling of 33120200003131 in words is "thirty-three trillion, one hundred twenty billion, two hundred million, three thousand, one hundred thirty-one".
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