Base | Representation |
---|---|
bin | 11110110110001011… |
… | …010110100000000011 |
3 | 10011111021101022000222 |
4 | 132312023112200003 |
5 | 1020313011401011 |
6 | 23114330133255 |
7 | 2251526361455 |
oct | 366613264003 |
9 | 104437338028 |
10 | 33121200131 |
11 | 13057065978 |
12 | 650428122b |
13 | 317ac03896 |
14 | 1862ba02d5 |
15 | cdcb5dddb |
hex | 7b62d6803 |
33121200131 has 2 divisors, whose sum is σ = 33121200132. Its totient is φ = 33121200130.
The previous prime is 33121200097. The next prime is 33121200137. The reversal of 33121200131 is 13100212133.
It is a strong prime.
It is an emirp because it is prime and its reverse (13100212133) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 33121200131 - 210 = 33121199107 is a prime.
It is a super-2 number, since 2×331212001312 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (33121200137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16560600065 + 16560600066.
It is an arithmetic number, because the mean of its divisors is an integer number (16560600066).
Almost surely, 233121200131 is an apocalyptic number.
33121200131 is a deficient number, since it is larger than the sum of its proper divisors (1).
33121200131 is an equidigital number, since it uses as much as digits as its factorization.
33121200131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 33121200131 its reverse (13100212133), we get a palindrome (46221412264).
The spelling of 33121200131 in words is "thirty-three billion, one hundred twenty-one million, two hundred thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •