331213043440131 has 8 divisors (see below), whose sum is σ = 441617485816080. Its totient is φ = 220808648345472.

The previous prime is 331213043440117. The next prime is 331213043440151. The reversal of 331213043440131 is 131044340312133.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 331213043440131 - 2¹¹ = 331213043438083 is a prime.

It is a super-2 number, since 2×331213043440131² (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 331213043440092 and 331213043440101.

It is not an unprimeable number, because it can be changed into a prime (331213043440151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10600431 + ... + 27835143.

It is an arithmetic number, because the mean of its divisors is an integer number (55202185727010).

Almost surely, 2^{331213043440131} is an apocalyptic number.

331213043440131 is a deficient number, since it is larger than the sum of its proper divisors (110404442375949).

331213043440131 is a wasteful number, since it uses less digits than its factorization.

331213043440131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23640645.

The product of its (nonzero) digits is 31104, while the sum is 33.

Adding to 331213043440131 its reverse (131044340312133), we get a palindrome (462257383752264).

The spelling of 331213043440131 in words is "three hundred thirty-one trillion, two hundred thirteen billion, forty-three million, four hundred forty thousand, one hundred thirty-one".