Base | Representation |
---|---|
bin | 110000001100101110101… |
… | …100011111111000110111 |
3 | 102201122101010200012102111 |
4 | 300030232230133320313 |
5 | 413231343004431403 |
6 | 11013334413351451 |
7 | 461204324455225 |
oct | 60145654377067 |
9 | 12648333605374 |
10 | 3312203202103 |
11 | 10677743a4374 |
12 | 455b16198587 |
13 | 1b045492bc53 |
14 | b6450a2db15 |
15 | 5b25841156d |
hex | 3032eb1fe37 |
3312203202103 has 4 divisors (see below), whose sum is σ = 3312206851240. Its totient is φ = 3312199552968.
The previous prime is 3312203202047. The next prime is 3312203202151. The reversal of 3312203202103 is 3012023022133.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 3312203202103 - 221 = 3312201104951 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3312203209103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 717601 + ... + 2671957.
It is an arithmetic number, because the mean of its divisors is an integer number (828051712810).
Almost surely, 23312203202103 is an apocalyptic number.
3312203202103 is a deficient number, since it is larger than the sum of its proper divisors (3649137).
3312203202103 is a wasteful number, since it uses less digits than its factorization.
3312203202103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3649136.
The product of its (nonzero) digits is 1296, while the sum is 22.
Adding to 3312203202103 its reverse (3012023022133), we get a palindrome (6324226224236).
The spelling of 3312203202103 in words is "three trillion, three hundred twelve billion, two hundred three million, two hundred two thousand, one hundred three".
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