Base | Representation |
---|---|
bin | 110000001100101111001… |
… | …011110110010010101010 |
3 | 102201122101201010201201021 |
4 | 300030233023312102222 |
5 | 413231402110422310 |
6 | 11013335305443054 |
7 | 461204454354121 |
oct | 60145713662252 |
9 | 12648351121637 |
10 | 3312211420330 |
11 | 1067778aa789a |
12 | 455b18aa048a |
13 | 1b04565487c7 |
14 | b6451b6cab8 |
15 | 5b258ed65da |
hex | 3032f2f64aa |
3312211420330 has 8 divisors (see below), whose sum is σ = 5961980556612. Its totient is φ = 1324884568128.
The previous prime is 3312211420261. The next prime is 3312211420363. The reversal of 3312211420330 is 330241122133.
3312211420330 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 2 ways, for example, as 3259581095761 + 52630324569 = 1805431^2 + 229413^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 3312211420295 and 3312211420304.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 165610571007 + ... + 165610571026.
Almost surely, 23312211420330 is an apocalyptic number.
3312211420330 is a deficient number, since it is larger than the sum of its proper divisors (2649769136282).
3312211420330 is a wasteful number, since it uses less digits than its factorization.
3312211420330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 331221142040.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 3312211420330 its reverse (330241122133), we get a palindrome (3642452542463).
The spelling of 3312211420330 in words is "three trillion, three hundred twelve billion, two hundred eleven million, four hundred twenty thousand, three hundred thirty".
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