Base | Representation |
---|---|
bin | 100101101001111100111100… |
… | …1110101100000000011110011 |
3 | 1121102202110011010021101110012 |
4 | 1023103321321311200003303 |
5 | 321403212241443013021 |
6 | 3132240551310525135 |
7 | 126523644243661154 |
oct | 11323717165400363 |
9 | 1542673133241405 |
10 | 331221332001011 |
11 | 965a01a5aa0771 |
12 | 31194ab5b067ab |
13 | 112a806476736a |
14 | 5bb12ab48392b |
15 | 2845c60ea135b |
hex | 12d3e79d600f3 |
331221332001011 has 2 divisors, whose sum is σ = 331221332001012. Its totient is φ = 331221332001010.
The previous prime is 331221332000927. The next prime is 331221332001029. The reversal of 331221332001011 is 110100233122133.
It is a strong prime.
It is an emirp because it is prime and its reverse (110100233122133) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 331221332001011 - 242 = 326823285489907 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (331221332001071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165610666000505 + 165610666000506.
It is an arithmetic number, because the mean of its divisors is an integer number (165610666000506).
Almost surely, 2331221332001011 is an apocalyptic number.
331221332001011 is a deficient number, since it is larger than the sum of its proper divisors (1).
331221332001011 is an equidigital number, since it uses as much as digits as its factorization.
331221332001011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 331221332001011 its reverse (110100233122133), we get a palindrome (441321565123144).
The spelling of 331221332001011 in words is "three hundred thirty-one trillion, two hundred twenty-one billion, three hundred thirty-two million, one thousand, eleven".
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