Base | Representation |
---|---|
bin | 11110110110010000… |
… | …000000110101100101 |
3 | 10011111100200101021201 |
4 | 132312100000311211 |
5 | 1020313320001432 |
6 | 23114412242501 |
7 | 2251542641221 |
oct | 366620006545 |
9 | 104440611251 |
10 | 33122422117 |
11 | 1305781aa84 |
12 | 6504770431 |
13 | 317b240b55 |
14 | 1862ddb781 |
15 | cdcd00ee7 |
hex | 7b6400d65 |
33122422117 has 2 divisors, whose sum is σ = 33122422118. Its totient is φ = 33122422116.
The previous prime is 33122422013. The next prime is 33122422121. The reversal of 33122422117 is 71122422133.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 18867494881 + 14254927236 = 137359^2 + 119394^2 .
It is a cyclic number.
It is not a de Polignac number, because 33122422117 - 27 = 33122421989 is a prime.
It is a super-4 number, since 4×331224221174 (a number of 43 digits) contains 4444 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (33122422187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16561211058 + 16561211059.
It is an arithmetic number, because the mean of its divisors is an integer number (16561211059).
Almost surely, 233122422117 is an apocalyptic number.
It is an amenable number.
33122422117 is a deficient number, since it is larger than the sum of its proper divisors (1).
33122422117 is an equidigital number, since it uses as much as digits as its factorization.
33122422117 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4032, while the sum is 28.
The spelling of 33122422117 in words is "thirty-three billion, one hundred twenty-two million, four hundred twenty-two thousand, one hundred seventeen".
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