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331234010413 is a prime number
BaseRepresentation
bin1001101000111110001…
…01011110010100101101
31011122222021020011011121
410310133011132110231
520411331401313123
6412100010220541
732634200430235
oct4643705362455
91148867204147
10331234010413
11118525a66649
1254241724751
1325309a65687
1412063410cc5
1589397e075d
hex4d1f15e52d

331234010413 has 2 divisors, whose sum is σ = 331234010414. Its totient is φ = 331234010412.

The previous prime is 331234010351. The next prime is 331234010431. The reversal of 331234010413 is 314010432133.

Together with next prime (331234010431) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 189178892809 + 142055117604 = 434947^2 + 376902^2 .

It is a cyclic number.

It is not a de Polignac number, because 331234010413 - 225 = 331200455981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (331234010113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165617005206 + 165617005207.

It is an arithmetic number, because the mean of its divisors is an integer number (165617005207).

Almost surely, 2331234010413 is an apocalyptic number.

It is an amenable number.

331234010413 is a deficient number, since it is larger than the sum of its proper divisors (1).

331234010413 is an equidigital number, since it uses as much as digits as its factorization.

331234010413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 331234010413 its reverse (314010432133), we get a palindrome (645244442546).

The spelling of 331234010413 in words is "three hundred thirty-one billion, two hundred thirty-four million, ten thousand, four hundred thirteen".