331300311230113 has 4 divisors (see below), whose sum is σ = 345704672587968. Its totient is φ = 316895949872260.

The previous prime is 331300311230101. The next prime is 331300311230191. The reversal of 331300311230113 is 311032113003133.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 331300311230113 - 2⁴¹ = 329101287974561 is a prime.

It is a super-3 number, since 3×331300311230113³ (a number of 45 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (331300311230513) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7202180678893 + ... + 7202180678938.

It is an arithmetic number, because the mean of its divisors is an integer number (86426168146992).

Almost surely, 2^{331300311230113} is an apocalyptic number.

It is an amenable number.

331300311230113 is a deficient number, since it is larger than the sum of its proper divisors (14404361357855).

331300311230113 is a wasteful number, since it uses less digits than its factorization.

331300311230113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14404361357854.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 331300311230113 its reverse (311032113003133), we get a palindrome (642332424233246).

The spelling of 331300311230113 in words is "three hundred thirty-one trillion, three hundred billion, three hundred eleven million, two hundred thirty thousand, one hundred thirteen".