Base | Representation |
---|---|
bin | 1001101001000110000… |
… | …10111010111110110111 |
3 | 1011200010220020122110121 |
4 | 10310203002322332313 |
5 | 20412000403401411 |
6 | 412110342232411 |
7 | 32635635235312 |
oct | 4644302727667 |
9 | 1150126218417 |
10 | 331300450231 |
11 | 11855a515893 |
12 | 5425ba25707 |
13 | 2531a75888a |
14 | 1206c187979 |
15 | 8940566571 |
hex | 4d230bafb7 |
331300450231 has 2 divisors, whose sum is σ = 331300450232. Its totient is φ = 331300450230.
The previous prime is 331300450193. The next prime is 331300450249. The reversal of 331300450231 is 132054003133.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 331300450231 - 221 = 331298353079 is a prime.
It is a super-2 number, since 2×3313004502312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 331300450196 and 331300450205.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (331300450931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165650225115 + 165650225116.
It is an arithmetic number, because the mean of its divisors is an integer number (165650225116).
Almost surely, 2331300450231 is an apocalyptic number.
331300450231 is a deficient number, since it is larger than the sum of its proper divisors (1).
331300450231 is an equidigital number, since it uses as much as digits as its factorization.
331300450231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3240, while the sum is 25.
Adding to 331300450231 its reverse (132054003133), we get a palindrome (463354453364).
The spelling of 331300450231 in words is "three hundred thirty-one billion, three hundred million, four hundred fifty thousand, two hundred thirty-one".
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