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3313012131113 = 19791674083947
BaseRepresentation
bin110000001101011110111…
…010010100010100101001
3102201201110111211001102012
4300031132322110110221
5413240022101143423
611013550551445305
7461233346320646
oct60153672242451
912651414731365
103313012131113
111068049a83743
12456101086835
131b05533ba079
14b64ca240dcd
155b2a444e078
hex3035ee94529

3313012131113 has 4 divisors (see below), whose sum is σ = 3314686217040. Its totient is φ = 3311338045188.

The previous prime is 3313012131109. The next prime is 3313012131119. The reversal of 3313012131113 is 3111312103133.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3313012131113 - 22 = 3313012131109 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (3313012131119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 837039995 + ... + 837043952.

It is an arithmetic number, because the mean of its divisors is an integer number (828671554260).

Almost surely, 23313012131113 is an apocalyptic number.

It is an amenable number.

3313012131113 is a deficient number, since it is larger than the sum of its proper divisors (1674085927).

3313012131113 is a wasteful number, since it uses less digits than its factorization.

3313012131113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1674085926.

The product of its (nonzero) digits is 486, while the sum is 23.

Adding to 3313012131113 its reverse (3111312103133), we get a palindrome (6424324234246).

The spelling of 3313012131113 in words is "three trillion, three hundred thirteen billion, twelve million, one hundred thirty-one thousand, one hundred thirteen".

Divisors: 1 1979 1674083947 3313012131113