Base | Representation |
---|---|
bin | 11110110110110000… |
… | …111001110101110101 |
3 | 10011111221220102120121 |
4 | 132312300321311311 |
5 | 1020323021403323 |
6 | 23115321131541 |
7 | 2252006141431 |
oct | 366660716565 |
9 | 104457812517 |
10 | 33131044213 |
11 | 13061679983 |
12 | 6507629bb1 |
13 | 317cc6c497 |
14 | 18642039c1 |
15 | cdd955a5d |
hex | 7b6c39d75 |
33131044213 has 2 divisors, whose sum is σ = 33131044214. Its totient is φ = 33131044212.
The previous prime is 33131044081. The next prime is 33131044231. The reversal of 33131044213 is 31244013133.
Together with next prime (33131044231) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 28332295684 + 4798748529 = 168322^2 + 69273^2 .
It is a cyclic number.
It is not a de Polignac number, because 33131044213 - 217 = 33130913141 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (33131044013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16565522106 + 16565522107.
It is an arithmetic number, because the mean of its divisors is an integer number (16565522107).
Almost surely, 233131044213 is an apocalyptic number.
It is an amenable number.
33131044213 is a deficient number, since it is larger than the sum of its proper divisors (1).
33131044213 is an equidigital number, since it uses as much as digits as its factorization.
33131044213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 33131044213 its reverse (31244013133), we get a palindrome (64375057346).
The spelling of 33131044213 in words is "thirty-three billion, one hundred thirty-one million, forty-four thousand, two hundred thirteen".
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