Base | Representation |
---|---|
bin | 1001101001000111010… |
… | …11101010100110001111 |
3 | 1011200011122100021202111 |
4 | 10310203223222212033 |
5 | 20412011122143043 |
6 | 412111403204451 |
7 | 32636125101535 |
oct | 4644353524617 |
9 | 1150148307674 |
10 | 331311131023 |
11 | 118565550494 |
12 | 54263516727 |
13 | 2531ca28282 |
14 | 1206d768155 |
15 | 894147609d |
hex | 4d23aea98f |
331311131023 has 4 divisors (see below), whose sum is σ = 332029810728. Its totient is φ = 330592451320.
The previous prime is 331311130933. The next prime is 331311131057. The reversal of 331311131023 is 320131113133.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 331311131023 - 217 = 331310999951 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 331311130985 and 331311131003.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (331311111023) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 359339161 + ... + 359340082.
It is an arithmetic number, because the mean of its divisors is an integer number (83007452682).
Almost surely, 2331311131023 is an apocalyptic number.
331311131023 is a deficient number, since it is larger than the sum of its proper divisors (718679705).
331311131023 is an equidigital number, since it uses as much as digits as its factorization.
331311131023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 718679704.
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 331311131023 its reverse (320131113133), we get a palindrome (651442244156).
The spelling of 331311131023 in words is "three hundred thirty-one billion, three hundred eleven million, one hundred thirty-one thousand, twenty-three".
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