Base | Representation |
---|---|
bin | 100101101010100110110100… |
… | …0010010110010011111100011 |
3 | 1121110002001012101222121202011 |
4 | 1023111031220102302133203 |
5 | 321411200400343031034 |
6 | 3132350140115533351 |
7 | 126533306120245363 |
oct | 11325155022623743 |
9 | 1543061171877664 |
10 | 331311232002019 |
11 | 96625339221065 |
12 | 311aa4052ba257 |
13 | 112b3690946429 |
14 | 5bb5798d909a3 |
15 | 2848273678864 |
hex | 12d53684b27e3 |
331311232002019 has 2 divisors, whose sum is σ = 331311232002020. Its totient is φ = 331311232002018.
The previous prime is 331311232001957. The next prime is 331311232002059. The reversal of 331311232002019 is 910200232113133.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 331311232002019 - 245 = 296126859913187 is a prime.
It is a super-3 number, since 3×3313112320020193 (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (331311232002059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165655616001009 + 165655616001010.
It is an arithmetic number, because the mean of its divisors is an integer number (165655616001010).
Almost surely, 2331311232002019 is an apocalyptic number.
331311232002019 is a deficient number, since it is larger than the sum of its proper divisors (1).
331311232002019 is an equidigital number, since it uses as much as digits as its factorization.
331311232002019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5832, while the sum is 31.
The spelling of 331311232002019 in words is "three hundred thirty-one trillion, three hundred eleven billion, two hundred thirty-two million, two thousand, nineteen".
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