Base | Representation |
---|---|
bin | 100101101010100111101010… |
… | …0001100101100100010110010 |
3 | 1121110002012212120110112020101 |
4 | 1023111033110030230202302 |
5 | 321411213102320002424 |
6 | 3132351035505503014 |
7 | 126533402022015565 |
oct | 11325172414544262 |
9 | 1543065776415211 |
10 | 331313042344114 |
11 | 966260880a9956 |
12 | 311aa82b641a6a |
13 | 112b38bba1797c |
14 | 5bb58cb59a4dc |
15 | 284832c576344 |
hex | 12d53d432c8b2 |
331313042344114 has 4 divisors (see below), whose sum is σ = 496969563516174. Its totient is φ = 165656521172056.
The previous prime is 331313042344111. The next prime is 331313042344129. The reversal of 331313042344114 is 411443240313133.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 328478179817089 + 2834862527025 = 18123967^2 + 1683705^2 .
It is not an unprimeable number, because it can be changed into a prime (331313042344111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82828260586027 + ... + 82828260586030.
Almost surely, 2331313042344114 is an apocalyptic number.
331313042344114 is a deficient number, since it is larger than the sum of its proper divisors (165656521172060).
331313042344114 is a wasteful number, since it uses less digits than its factorization.
331313042344114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 165656521172059.
The product of its (nonzero) digits is 124416, while the sum is 37.
Adding to 331313042344114 its reverse (411443240313133), we get a palindrome (742756282657247).
The spelling of 331313042344114 in words is "three hundred thirty-one trillion, three hundred thirteen billion, forty-two million, three hundred forty-four thousand, one hundred fourteen".
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