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33132010433 is a prime number
BaseRepresentation
bin11110110110110100…
…100101101111000001
310011112000201111222112
4132312310211233001
51020323243313213
623115353545105
72252020304414
oct366664455701
9104460644875
1033132010433
1113062179905
126507a15195
13318021a202
1418643b5b7b
15cdda96ea8
hex7b6d25bc1

33132010433 has 2 divisors, whose sum is σ = 33132010434. Its totient is φ = 33132010432.

The previous prime is 33132010397. The next prime is 33132010459. The reversal of 33132010433 is 33401023133.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 17096347009 + 16035663424 = 130753^2 + 126632^2 .

It is a cyclic number.

It is not a de Polignac number, because 33132010433 - 212 = 33132006337 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 33132010399 and 33132010408.

It is not a weakly prime, because it can be changed into another prime (33132010033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16566005216 + 16566005217.

It is an arithmetic number, because the mean of its divisors is an integer number (16566005217).

Almost surely, 233132010433 is an apocalyptic number.

It is an amenable number.

33132010433 is a deficient number, since it is larger than the sum of its proper divisors (1).

33132010433 is an equidigital number, since it uses as much as digits as its factorization.

33132010433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944, while the sum is 23.

Adding to 33132010433 its reverse (33401023133), we get a palindrome (66533033566).

The spelling of 33132010433 in words is "thirty-three billion, one hundred thirty-two million, ten thousand, four hundred thirty-three".