Base | Representation |
---|---|
bin | 110000001101110001111… |
… | …011001010100000000011 |
3 | 102201202021202001101002021 |
4 | 300031301323022200003 |
5 | 413241200231321011 |
6 | 11014042344502311 |
7 | 461244301556044 |
oct | 60156173124003 |
9 | 12652252041067 |
10 | 3313331120131 |
11 | 10681a304792a |
12 | 45618ba7a997 |
13 | 1b05a4506076 |
14 | b651a7588cb |
15 | 5b2c245e471 |
hex | 30371eca803 |
3313331120131 has 2 divisors, whose sum is σ = 3313331120132. Its totient is φ = 3313331120130.
The previous prime is 3313331120129. The next prime is 3313331120137. The reversal of 3313331120131 is 1310211333133.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3313331120131 - 21 = 3313331120129 is a prime.
It is a super-2 number, since 2×33133311201312 (a number of 26 digits) contains 22 as substring.
Together with 3313331120129, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 3313331120096 and 3313331120105.
It is not a weakly prime, because it can be changed into another prime (3313331120137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1656665560065 + 1656665560066.
It is an arithmetic number, because the mean of its divisors is an integer number (1656665560066).
Almost surely, 23313331120131 is an apocalyptic number.
3313331120131 is a deficient number, since it is larger than the sum of its proper divisors (1).
3313331120131 is an equidigital number, since it uses as much as digits as its factorization.
3313331120131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 3313331120131 its reverse (1310211333133), we get a palindrome (4623542453264).
The spelling of 3313331120131 in words is "three trillion, three hundred thirteen billion, three hundred thirty-one million, one hundred twenty thousand, one hundred thirty-one".
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