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331342101243193 is a prime number
BaseRepresentation
bin100101101010110101001100…
…0001111100110010100111001
31121110011222212201220112211211
41023111222120033212110321
5321412202110404240233
63132412243202523121
7126535451103414145
oct11325523017462471
91543158781815754
10331342101243193
119663743a098927
12311b439b3664a1
13112b6570125701
145bb7086a2a225
152848e7d7555cd
hex12d5a983e6539

331342101243193 has 2 divisors, whose sum is σ = 331342101243194. Its totient is φ = 331342101243192.

The previous prime is 331342101243149. The next prime is 331342101243289. The reversal of 331342101243193 is 391342101243133.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 248365086717609 + 82977014525584 = 15759603^2 + 9109172^2 .

It is a cyclic number.

It is not a de Polignac number, because 331342101243193 - 29 = 331342101242681 is a prime.

It is a super-2 number, since 2×3313421012431932 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (331342101643193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165671050621596 + 165671050621597.

It is an arithmetic number, because the mean of its divisors is an integer number (165671050621597).

Almost surely, 2331342101243193 is an apocalyptic number.

It is an amenable number.

331342101243193 is a deficient number, since it is larger than the sum of its proper divisors (1).

331342101243193 is an equidigital number, since it uses as much as digits as its factorization.

331342101243193 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 139968, while the sum is 40.

The spelling of 331342101243193 in words is "three hundred thirty-one trillion, three hundred forty-two billion, one hundred one million, two hundred forty-three thousand, one hundred ninety-three".