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331342101243149 is a prime number
BaseRepresentation
bin100101101010110101001100…
…0001111100110010100001101
31121110011222212201220112210012
41023111222120033212110031
5321412202110404240044
63132412243202523005
7126535451103414053
oct11325523017462415
91543158781815705
10331342101243149
119663743a098897
12311b439b366465
13112b6570125699
145bb7086a2a1d3
152848e7d75559e
hex12d5a983e650d

331342101243149 has 2 divisors, whose sum is σ = 331342101243150. Its totient is φ = 331342101243148.

The previous prime is 331342101243067. The next prime is 331342101243193. The reversal of 331342101243149 is 941342101243133.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 303123769202500 + 28218332040649 = 17410450^2 + 5312093^2 .

It is an emirp because it is prime and its reverse (941342101243133) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 331342101243149 - 236 = 331273381766413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (331342101243649) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165671050621574 + 165671050621575.

It is an arithmetic number, because the mean of its divisors is an integer number (165671050621575).

Almost surely, 2331342101243149 is an apocalyptic number.

It is an amenable number.

331342101243149 is a deficient number, since it is larger than the sum of its proper divisors (1).

331342101243149 is an equidigital number, since it uses as much as digits as its factorization.

331342101243149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 186624, while the sum is 41.

The spelling of 331342101243149 in words is "three hundred thirty-one trillion, three hundred forty-two billion, one hundred one million, two hundred forty-three thousand, one hundred forty-nine".