Base | Representation |
---|---|
bin | 110000001110100111101… |
… | …100000011110001000111 |
3 | 102201211121121100020002020 |
4 | 300032213230003301013 |
5 | 413300022140130210 |
6 | 11014312050014223 |
7 | 461305533535431 |
oct | 60164754036107 |
9 | 12654547306066 |
10 | 3314233130055 |
11 | 1068616222281 |
12 | 4563a1b77373 |
13 | 1b06b9354553 |
14 | b65a4479651 |
15 | 5b326736770 |
hex | 303a7b03c47 |
3314233130055 has 32 divisors (see below), whose sum is σ = 5362576358400. Its totient is φ = 1747658195712.
The previous prime is 3314233130041. The next prime is 3314233130059. The reversal of 3314233130055 is 5500313324133.
It is not a de Polignac number, because 3314233130055 - 219 = 3314232605767 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3314233129998 and 3314233130025.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3314233130059) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 52138702 + ... + 52202228.
It is an arithmetic number, because the mean of its divisors is an integer number (167580511200).
Almost surely, 23314233130055 is an apocalyptic number.
3314233130055 is a deficient number, since it is larger than the sum of its proper divisors (2048343228345).
3314233130055 is a wasteful number, since it uses less digits than its factorization.
3314233130055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 102703.
The product of its (nonzero) digits is 48600, while the sum is 33.
Adding to 3314233130055 its reverse (5500313324133), we get a palindrome (8814546454188).
The spelling of 3314233130055 in words is "three trillion, three hundred fourteen billion, two hundred thirty-three million, one hundred thirty thousand, fifty-five".
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