Base | Representation |
---|---|
bin | 100101101011011110100110… |
… | …0110100101100011100110011 |
3 | 1121110111111102100110020221010 |
4 | 1023112331030310230130303 |
5 | 321420131222213244103 |
6 | 3132521151403202003 |
7 | 126545046616241022 |
oct | 11326751464543463 |
9 | 1543444370406833 |
10 | 331431030212403 |
11 | 96671124190700 |
12 | 31209679516303 |
13 | 112c1a7309aa54 |
14 | 5bbb4c15aa8b9 |
15 | 284b435a6e903 |
hex | 12d6f4cd2c733 |
331431030212403 has 12 divisors (see below), whose sum is σ = 485733631055624. Its totient is φ = 200867291037600.
The previous prime is 331431030212393. The next prime is 331431030212449. The reversal of 331431030212403 is 304212030134133.
It is not a de Polignac number, because 331431030212403 - 25 = 331431030212371 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (331431030212453) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 456516570178 + ... + 456516570903.
Almost surely, 2331431030212403 is an apocalyptic number.
331431030212403 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
331431030212403 is a deficient number, since it is larger than the sum of its proper divisors (154302600843221).
331431030212403 is a wasteful number, since it uses less digits than its factorization.
331431030212403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 913033141106 (or 913033141095 counting only the distinct ones).
The product of its (nonzero) digits is 15552, while the sum is 30.
Adding to 331431030212403 its reverse (304212030134133), we get a palindrome (635643060346536).
The spelling of 331431030212403 in words is "three hundred thirty-one trillion, four hundred thirty-one billion, thirty million, two hundred twelve thousand, four hundred three".
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