Base | Representation |
---|---|
bin | 110000001110101101001… |
… | …000011000111111101101 |
3 | 102201211211222011102001111 |
4 | 300032231020120333231 |
5 | 413300214024134432 |
6 | 11014325111112021 |
7 | 461311022640322 |
oct | 60165510307755 |
9 | 12654758142044 |
10 | 3314324443117 |
11 | 1068662820116 |
12 | 456408672611 |
13 | 1b070224604c |
14 | b65b2648b49 |
15 | 5b32e772347 |
hex | 303ad218fed |
3314324443117 has 2 divisors, whose sum is σ = 3314324443118. Its totient is φ = 3314324443116.
The previous prime is 3314324443049. The next prime is 3314324443123. The reversal of 3314324443117 is 7113444234133.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2263020783556 + 1051303659561 = 1504334^2 + 1025331^2 .
It is a cyclic number.
It is not a de Polignac number, because 3314324443117 - 223 = 3314316054509 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3314324443117.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3314324443517) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1657162221558 + 1657162221559.
It is an arithmetic number, because the mean of its divisors is an integer number (1657162221559).
Almost surely, 23314324443117 is an apocalyptic number.
It is an amenable number.
3314324443117 is a deficient number, since it is larger than the sum of its proper divisors (1).
3314324443117 is an equidigital number, since it uses as much as digits as its factorization.
3314324443117 is an evil number, because the sum of its binary digits is even.
The product of its digits is 290304, while the sum is 40.
The spelling of 3314324443117 in words is "three trillion, three hundred fourteen billion, three hundred twenty-four million, four hundred forty-three thousand, one hundred seventeen".
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