Base | Representation |
---|---|
bin | 110000001110101110000… |
… | …100001010101011010111 |
3 | 102201211220001122112020122 |
4 | 300032232010022223113 |
5 | 413300232032104421 |
6 | 11014330431022155 |
7 | 461311303063406 |
oct | 60165604125327 |
9 | 12654801575218 |
10 | 3314340113111 |
11 | 1068670653225 |
12 | 45641196a95b |
13 | 1b0705571631 |
14 | b65b476763d |
15 | 5b330d1a2ab |
hex | 303ae10aad7 |
3314340113111 has 2 divisors, whose sum is σ = 3314340113112. Its totient is φ = 3314340113110.
The previous prime is 3314340113089. The next prime is 3314340113171. The reversal of 3314340113111 is 1113110434133.
It is a weak prime.
It is an emirp because it is prime and its reverse (1113110434133) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3314340113111 - 210 = 3314340112087 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3314340113171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1657170056555 + 1657170056556.
It is an arithmetic number, because the mean of its divisors is an integer number (1657170056556).
Almost surely, 23314340113111 is an apocalyptic number.
3314340113111 is a deficient number, since it is larger than the sum of its proper divisors (1).
3314340113111 is an equidigital number, since it uses as much as digits as its factorization.
3314340113111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 26.
Adding to 3314340113111 its reverse (1113110434133), we get a palindrome (4427450547244).
The spelling of 3314340113111 in words is "three trillion, three hundred fourteen billion, three hundred forty million, one hundred thirteen thousand, one hundred eleven".
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