Base | Representation |
---|---|
bin | 110000001111001111101… |
… | …011100101010110110101 |
3 | 102201220100100212201202122 |
4 | 300033033223211112311 |
5 | 413302410422003013 |
6 | 11014502415045325 |
7 | 461331261615062 |
oct | 60171753452665 |
9 | 12656310781678 |
10 | 3314904094133 |
11 | 106892aa3a545 |
12 | 45654a810845 |
13 | 1b0795368708 |
14 | b6629615c69 |
15 | 5b3655c0a08 |
hex | 303cfae55b5 |
3314904094133 has 2 divisors, whose sum is σ = 3314904094134. Its totient is φ = 3314904094132.
The previous prime is 3314904094097. The next prime is 3314904094157.
3314904094133 is nontrivially palindromic in base 10.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3291386951524 + 23517142609 = 1814218^2 + 153353^2 .
It is a palprime.
It is a cyclic number.
It is not a de Polignac number, because 3314904094133 - 28 = 3314904093877 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3314904094193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1657452047066 + 1657452047067.
It is an arithmetic number, because the mean of its divisors is an integer number (1657452047067).
Almost surely, 23314904094133 is an apocalyptic number.
It is an amenable number.
3314904094133 is a deficient number, since it is larger than the sum of its proper divisors (1).
3314904094133 is an equidigital number, since it uses as much as digits as its factorization.
3314904094133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 419904, while the sum is 44.
The spelling of 3314904094133 in words is "three trillion, three hundred fourteen billion, nine hundred four million, ninety-four thousand, one hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •