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3315121303397 is a prime number
BaseRepresentation
bin110000001111011100101…
…000001010111101100101
3102201220220111121002212012
4300033130220022331211
5413303332023202042
611014540134404005
7461336540066201
oct60173450127545
912656814532765
103315121303397
111068a31607032
124565ab500605
131b07cb369ac7
14b664a3d7b01
155b3796c8e82
hex303dca0af65

3315121303397 has 2 divisors, whose sum is σ = 3315121303398. Its totient is φ = 3315121303396.

The previous prime is 3315121303393. The next prime is 3315121303421. The reversal of 3315121303397 is 7933031215133.

3315121303397 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2994401828356 + 320719475041 = 1730434^2 + 566321^2 .

It is a cyclic number.

It is not a de Polignac number, because 3315121303397 - 22 = 3315121303393 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3315121303393) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1657560651698 + 1657560651699.

It is an arithmetic number, because the mean of its divisors is an integer number (1657560651699).

Almost surely, 23315121303397 is an apocalyptic number.

It is an amenable number.

3315121303397 is a deficient number, since it is larger than the sum of its proper divisors (1).

3315121303397 is an equidigital number, since it uses as much as digits as its factorization.

3315121303397 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 153090, while the sum is 41.

The spelling of 3315121303397 in words is "three trillion, three hundred fifteen billion, one hundred twenty-one million, three hundred three thousand, three hundred ninety-seven".