Base | Representation |
---|---|
bin | 1111000100110111100111… |
… | …00110110011001011101101 |
3 | 11100101100202210202102110210 |
4 | 13202123303212303023231 |
5 | 13321133104011001013 |
6 | 154302040434453033 |
7 | 6661125303506025 |
oct | 742336346631355 |
9 | 140340683672423 |
10 | 33152644625133 |
11 | a621a5966a990 |
12 | 3875255734179 |
13 | 15663863b7337 |
14 | 82884cd70a85 |
15 | 3c759a394cc3 |
hex | 1e26f39b32ed |
33152644625133 has 16 divisors (see below), whose sum is σ = 48230281783296. Its totient is φ = 20089073045040.
The previous prime is 33152644625131. The next prime is 33152644625171.
33152644625133 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 33152644625133 - 21 = 33152644625131 is a prime.
It is a super-3 number, since 3×331526446251333 (a number of 42 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (33152644625131) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 85775485 + ... + 86161122.
It is an arithmetic number, because the mean of its divisors is an integer number (3014392611456).
Almost surely, 233152644625133 is an apocalyptic number.
33152644625133 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
It is an amenable number.
33152644625133 is a deficient number, since it is larger than the sum of its proper divisors (15077637158163).
33152644625133 is a wasteful number, since it uses less digits than its factorization.
33152644625133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 171942464.
The product of its digits is 4665600, while the sum is 48.
The spelling of 33152644625133 in words is "thirty-three trillion, one hundred fifty-two billion, six hundred forty-four million, six hundred twenty-five thousand, one hundred thirty-three".
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