Base | Representation |
---|---|
bin | 1001101001100001100… |
… | …10111100110000111101 |
3 | 1011200201222100010011122 |
4 | 10310300302330300331 |
5 | 20412433433104003 |
6 | 412145303000325 |
7 | 32644436141531 |
oct | 4646062746075 |
9 | 1150658303148 |
10 | 331531144253 |
11 | 118668762701 |
12 | 543051390a5 |
13 | 2535649ba0a |
14 | 12090a79bc1 |
15 | 8955935238 |
hex | 4d30cbcc3d |
331531144253 has 2 divisors, whose sum is σ = 331531144254. Its totient is φ = 331531144252.
The previous prime is 331531144249. The next prime is 331531144261. The reversal of 331531144253 is 352441135133.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 264086015449 + 67445128804 = 513893^2 + 259702^2 .
It is an emirp because it is prime and its reverse (352441135133) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 331531144253 - 22 = 331531144249 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (331531164253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165765572126 + 165765572127.
It is an arithmetic number, because the mean of its divisors is an integer number (165765572127).
Almost surely, 2331531144253 is an apocalyptic number.
It is an amenable number.
331531144253 is a deficient number, since it is larger than the sum of its proper divisors (1).
331531144253 is an equidigital number, since it uses as much as digits as its factorization.
331531144253 is an evil number, because the sum of its binary digits is even.
The product of its digits is 64800, while the sum is 35.
Adding to 331531144253 its reverse (352441135133), we get a palindrome (683972279386).
The spelling of 331531144253 in words is "three hundred thirty-one billion, five hundred thirty-one million, one hundred forty-four thousand, two hundred fifty-three".
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