Base | Representation |
---|---|
bin | 100101101111101101010010… |
… | …1000011100110111101001111 |
3 | 1121112120001212012122002020221 |
4 | 1023133122211003212331033 |
5 | 322004142223230231111 |
6 | 3134044205334452211 |
7 | 126635046034256206 |
oct | 11337324503467517 |
9 | 1545501765562227 |
10 | 332012331102031 |
11 | 968757033aa878 |
12 | 312a2269b04067 |
13 | 11334822a0a4b8 |
14 | 5bdb6a823c23d |
15 | 285b608e8a371 |
hex | 12df6a50e6f4f |
332012331102031 has 4 divisors (see below), whose sum is σ = 332012605180912. Its totient is φ = 332012057023152.
The previous prime is 332012331101987. The next prime is 332012331102083. The reversal of 332012331102031 is 130201133210233.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-332012331102031 is a prime.
It is a super-2 number, since 2×3320123311020312 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 332012331101987 and 332012331102005.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (332012331109031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 135214275 + ... + 137647828.
It is an arithmetic number, because the mean of its divisors is an integer number (83003151295228).
Almost surely, 2332012331102031 is an apocalyptic number.
332012331102031 is a deficient number, since it is larger than the sum of its proper divisors (274078881).
332012331102031 is a wasteful number, since it uses less digits than its factorization.
332012331102031 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 274078880.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 332012331102031 its reverse (130201133210233), we get a palindrome (462213464312264).
The spelling of 332012331102031 in words is "three hundred thirty-two trillion, twelve billion, three hundred thirty-one million, one hundred two thousand, thirty-one".
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