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3320310000131 = 4712370460497
BaseRepresentation
bin110000010100010001111…
…001011110101000000011
3102202102022010001012200022
4300110101321132220003
5413344443330001011
611021155050244055
7461612243223005
oct60242171365003
912672263035608
103320310000131
111070154486753
124575b912662b
131b1147325b67
14b69bd578375
155b57eea58db
hex30511e5ea03

3320310000131 has 4 divisors (see below), whose sum is σ = 3320380507752. Its totient is φ = 3320239492512.

The previous prime is 3320310000121. The next prime is 3320310000173. The reversal of 3320310000131 is 1310000130233.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 3320310000131 - 26 = 3320310000067 is a prime.

It is a super-2 number, since 2×33203100001312 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3320310000121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35183126 + ... + 35277371.

It is an arithmetic number, because the mean of its divisors is an integer number (830095126938).

Almost surely, 23320310000131 is an apocalyptic number.

3320310000131 is a deficient number, since it is larger than the sum of its proper divisors (70507621).

3320310000131 is an equidigital number, since it uses as much as digits as its factorization.

3320310000131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 70507620.

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 3320310000131 its reverse (1310000130233), we get a palindrome (4630310130364).

The spelling of 3320310000131 in words is "three trillion, three hundred twenty billion, three hundred ten million, one hundred thirty-one", and thus it is an aban number.

Divisors: 1 47123 70460497 3320310000131