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3321001110113 is a prime number
BaseRepresentation
bin110000010100111011000…
…101110110101001100001
3102202111002021111020100022
4300110323011312221201
5413402402241010423
611021351415203225
7461635334446631
oct60247305665141
912674067436308
103321001110113
111070479603925
12457770676515
131b122757198b
14b6a4727a6c1
155b5c09bddc8
hex3053b176a61

3321001110113 has 2 divisors, whose sum is σ = 3321001110114. Its totient is φ = 3321001110112.

The previous prime is 3321001110103. The next prime is 3321001110173. The reversal of 3321001110113 is 3110111001233.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3278065954849 + 42935155264 = 1810543^2 + 207208^2 .

It is a cyclic number.

It is not a de Polignac number, because 3321001110113 - 28 = 3321001109857 is a prime.

It is a super-2 number, since 2×33210011101132 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3321001110091 and 3321001110100.

It is not a weakly prime, because it can be changed into another prime (3321001110103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1660500555056 + 1660500555057.

It is an arithmetic number, because the mean of its divisors is an integer number (1660500555057).

Almost surely, 23321001110113 is an apocalyptic number.

It is an amenable number.

3321001110113 is a deficient number, since it is larger than the sum of its proper divisors (1).

3321001110113 is an equidigital number, since it uses as much as digits as its factorization.

3321001110113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 3321001110113 its reverse (3110111001233), we get a palindrome (6431112111346).

The spelling of 3321001110113 in words is "three trillion, three hundred twenty-one billion, one million, one hundred ten thousand, one hundred thirteen".