332100113 has 2 divisors, whose sum is σ = 332100114. Its totient is φ = 332100112.

The previous prime is 332100101. The next prime is 332100127. The reversal of 332100113 is 311001233.

It is an a-pointer prime, because the next prime (332100127) can be obtained adding 332100113 to its sum of digits (14).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 244359424 + 87740689 = 15632^2 + 9367^2 .

It is an emirp because it is prime and its reverse (311001233) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 332100113 - 2²⁴ = 315322897 is a prime.

It is a super-2 number, since 2×332100113² = 220580970109225538, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (332100133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 166050056 + 166050057.

It is an arithmetic number, because the mean of its divisors is an integer number (166050057).

Almost surely, 2^332100113 is an apocalyptic number.

It is an amenable number.

332100113 is a deficient number, since it is larger than the sum of its proper divisors (1).

332100113 is an equidigital number, since it uses as much as digits as its factorization.

332100113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 14.

The square root of 332100113 is about 18223.6141585581. The cubic root of 332100113 is about 692.5051504698.

Adding to 332100113 its reverse (311001233), we get a palindrome (643101346).

The spelling of 332100113 in words is "three hundred thirty-two million, one hundred thousand, one hundred thirteen".