Base | Representation |
---|---|
bin | 1111000110100110010110… |
… | …11011011110011101000101 |
3 | 11100121001020100202000002101 |
4 | 13203103023123132131011 |
5 | 13323121340112011044 |
6 | 154345232252112101 |
7 | 6665331542005342 |
oct | 743231333363505 |
9 | 140531210660071 |
10 | 33212100110149 |
11 | a645199746864 |
12 | 3884889165631 |
13 | 156bb700a47bc |
14 | 82b68d3a17c9 |
15 | 3c8dc9dd9cd4 |
hex | 1e34cb6de745 |
33212100110149 has 2 divisors, whose sum is σ = 33212100110150. Its totient is φ = 33212100110148.
The previous prime is 33212100110093. The next prime is 33212100110179. The reversal of 33212100110149 is 94101100121233.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 32739109676100 + 472990434049 = 5721810^2 + 687743^2 .
It is a cyclic number.
It is not a de Polignac number, because 33212100110149 - 215 = 33212100077381 is a prime.
It is a super-2 number, since 2×332121001101492 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (33212100110179) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16606050055074 + 16606050055075.
It is an arithmetic number, because the mean of its divisors is an integer number (16606050055075).
Almost surely, 233212100110149 is an apocalyptic number.
It is an amenable number.
33212100110149 is a deficient number, since it is larger than the sum of its proper divisors (1).
33212100110149 is an equidigital number, since it uses as much as digits as its factorization.
33212100110149 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 28.
The spelling of 33212100110149 in words is "thirty-three trillion, two hundred twelve billion, one hundred million, one hundred ten thousand, one hundred forty-nine".
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