Base | Representation |
---|---|
bin | 1001101010100111111… |
… | …11000110001010010111 |
3 | 1011202021010020212120121 |
4 | 10311103333012022113 |
5 | 20420141102443111 |
6 | 412324033012411 |
7 | 32665165302013 |
oct | 4652377061227 |
9 | 1152233225517 |
10 | 332121531031 |
11 | 118940a44a64 |
12 | 5444a9b4107 |
13 | 2541b8acac4 |
14 | 1210923d543 |
15 | 898c6a4871 |
hex | 4d53fc6297 |
332121531031 has 2 divisors, whose sum is σ = 332121531032. Its totient is φ = 332121531030.
The previous prime is 332121531017. The next prime is 332121531073. The reversal of 332121531031 is 130135121233.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 332121531031 - 29 = 332121530519 is a prime.
It is a super-2 number, since 2×3321215310312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 332121530987 and 332121531005.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (332121531011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 166060765515 + 166060765516.
It is an arithmetic number, because the mean of its divisors is an integer number (166060765516).
Almost surely, 2332121531031 is an apocalyptic number.
332121531031 is a deficient number, since it is larger than the sum of its proper divisors (1).
332121531031 is an equidigital number, since it uses as much as digits as its factorization.
332121531031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1620, while the sum is 25.
Adding to 332121531031 its reverse (130135121233), we get a palindrome (462256652264).
The spelling of 332121531031 in words is "three hundred thirty-two billion, one hundred twenty-one million, five hundred thirty-one thousand, thirty-one".
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